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函数Fxsinx根号3Cosx

函数fx=sinx-根号3*cosx(x∈【-π,0】)=2(sinx/2-√3cosx/2)=2sin(x-π/3)∵x∈[-π,0]∴x-π/3∈[-4π/3,-π/3]∴函数的单调递增区间是[-π/2,-π/3]

解由f(x)=sinx-√3cosx+2=2(1/2sinx-√3/2cosx)+2=2sin(x-π/3)+2由x属于[2π/3,4π/3]即2π/3≤x≤4π/3即π/3≤x-π/3≤π故当x-π/3=π/2时,即x=5π/6时,y有最大值y=2*1+2=4当x-π/3=π时,即x=4π/3时,y有

f(x)=sinx(sinx+√3cosx)=(sinx)^2+根号3sinxcosx=(1-cos2x)/2+根号3/2 sin2x=sin2x*cosπ/6-cos2x sinπ/6+1/2=sin(2x-π/6)+1/2其中x∈[0,π/2],那么2x-π/6属于[-π/6,5π/6]所以,-1/2

f(x)=sinx/3cosx/3+根号3cos^2x/3 =1/2 sin2x/3+根号3 /2 (cos2x/3+1) =sin(2x/3+pi/3)+根号3 /2对称中心的横坐标满足sin(2x/3+pi/3)=0,2x/3+pi/3=k pix=(3k-1)/2 piT = 2π,对称中心为x=(3k-1)/2 pi祝您在新的一年一帆风顺,二龙腾飞,三羊开泰,四季平安,五福临门,六六大顺,七星高照,八方来财,九九同心,十全十美.

解fx=sinx的平方+根号3sinxcosx =(1-cos2x)/2+√3/2sin2x =√3/2sin2x-cos2x/2+1/2 =sin(2x-π/6)+1/2 故函数的周期T=2π/2=π.

f(x)=sinx+根号3cosx=2*sin(x+pi/3) 1. T=2pi2. x用x-pi/3代替:y=sinx单调增区间:【0,pi/2】

f(x) = sinx+√3 cosx= 2(sinxcosπ/3+cosxsinπ/3)= 2sin(x+π/3)周期=2π/1=2πx+π/3∈(2kπ+π/2,2kπ+3π/2)时递减∴递减区间为(2kπ+π/6,2kπ+7π/6),其中k∈Z

f(x)=sinx+√3cosx =2(1/2sinx+√3/2cosx) =2(cosπ/3sinx+sinπ/3cosx) =2sin(x+π/3) 所以易得最大值为2,最小值为-2.

f(x)=sinx-根号3cosx=2(1/2sinx-根号3/2cosx)=2(sinxcosπ/3-cosx sinπ/3)=2sin(x-π/3)最小正周期:2π

你好:f(x)=√3sinxcosxcosx+1/2 =√3sinxcosx1/2(1-cosx)+1/2 =√3/2sin2x+1/2cosx-1/2+1/2 =sin(2x+π/6) T=2π/2=π 希望能帮助你:

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